Tuesday, September 25, 2018

PROBLEM ON TRAIN ALL IMPORTANT CONCEPT




1.    km/hr to m/s conversion:

a km/hr =
a x
5
m/s.
18
2.    m/s to km/hr conversion:
a m/s =
a x
18
km/hr.
5
4.    Time taken by a train of length l metres to pass a pole or standing man or a signal post is equal to the time taken by the train to cover l metres.
5.    Time taken by a train of length l metres to pass a stationery object of length b metres is the time taken by the train to cover (l + b) metres.
6.    Suppose two trains or two objects bodies are moving in the same direction at u m/s and v m/s, where u > v, then their relative speed is = (u - v) m/s.
7.    Suppose two trains or two objects bodies are moving in opposite directions at u m/s and v m/s, then their relative speed is = (u + v) m/s.
8.    If two trains of length a metres and b metres are moving in opposite directions at u m/s and v m/s, then:
The time taken by the trains to cross each other =
(a + b)
sec.
(u + v)
9.    If two trains of length a metres and b metres are moving in the same direction at u m/s and v m/s, then:
The time taken by the faster train to cross the slower train =
(a + b)
sec.
(u - v)
10.  If two trains (or bodies) start at the same time from points A and B towards each other and after crossing they take a and b sec in reaching B and A respectively, then:
(A's speed) : (B's speed) = (b : a)

                                             


                                                  PROBLEMS BASED ON TRAIN
Eg:-1
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:

SOLUTION:-

Speed of the train relative to man =
125
m/sec
10

   =
25
m/sec.
2

   =
25
x
18
km/hr
2
5
   = 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
 x - 5 = 45           x = 50 km/hr.
Eg:-2
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?

SOLUTION:-

Speed =
54 x
5
m/sec = 15 m/sec.
18
Length of the train = (15 x 20) m = 300 m.
Let the length of the platform be x metres.
Then,
x + 300
= 15
36
 x + 300 = 540
 x = 240 m.

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